going over a couple questions see attachment
The answer to the first question is related to the last answer I gave you. Changing where the zero point is doesn't actually do anything, because the gradient is all that matters.
ok i thought so too
2nd one i thought b and d but that was wrong
The monopole term vanishes if the total charge of the arrangement is zero. That immediately eliminates B,C, and D. The dipole term survives if the total charge is zero *but* the positives and negatives are still grouped together, forming two electric poles. Hence, dipole. This is the case for A and also for E.
wait a second, but how is the total charge of the arrangement zero for B
Everything is positive.
It's NOT zero which is the point.
If the total charge is nonzero, then the monopole term survives, so the dipole term won't be the first nonzero term.
oh there is no dipole term from monopoles, i see lol
Yup. It goes monopole, dipole, quadrupole, octupole, etc.
multipole expansions always decrease the higher pole right
as the v ~ 1/(r^n) for npole
The potential goes like 1/r for a monopole, 1/r^2 for a dipole, 1/r^3 for a quadrupole, etc.
yeah
i wonder what 16 pole looks like
just what you'd think -- it's the next logical step after the octupole.
Like a flower with sixteen petals.
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