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Physics 8 Online
OpenStudy (dan815):

going over a couple questions see attachment

OpenStudy (dan815):

OpenStudy (anonymous):

The answer to the first question is related to the last answer I gave you. Changing where the zero point is doesn't actually do anything, because the gradient is all that matters.

OpenStudy (dan815):

ok i thought so too

OpenStudy (dan815):

2nd one i thought b and d but that was wrong

OpenStudy (anonymous):

The monopole term vanishes if the total charge of the arrangement is zero. That immediately eliminates B,C, and D. The dipole term survives if the total charge is zero *but* the positives and negatives are still grouped together, forming two electric poles. Hence, dipole. This is the case for A and also for E.

OpenStudy (dan815):

wait a second, but how is the total charge of the arrangement zero for B

OpenStudy (anonymous):

Everything is positive.

OpenStudy (anonymous):

It's NOT zero which is the point.

OpenStudy (anonymous):

If the total charge is nonzero, then the monopole term survives, so the dipole term won't be the first nonzero term.

OpenStudy (dan815):

oh there is no dipole term from monopoles, i see lol

OpenStudy (anonymous):

Yup. It goes monopole, dipole, quadrupole, octupole, etc.

OpenStudy (dan815):

multipole expansions always decrease the higher pole right

OpenStudy (dan815):

as the v ~ 1/(r^n) for npole

OpenStudy (anonymous):

The potential goes like 1/r for a monopole, 1/r^2 for a dipole, 1/r^3 for a quadrupole, etc.

OpenStudy (dan815):

yeah

OpenStudy (dan815):

i wonder what 16 pole looks like

OpenStudy (anonymous):

just what you'd think -- it's the next logical step after the octupole.

OpenStudy (anonymous):

Like a flower with sixteen petals.

OpenStudy (dan815):

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