What is the equation of the following graph?
Its a negative parabola, where a < 0
okay...
The parent function for parabolas is f(x) = x^2 You can use the parent function to apply the needed transformations to get the equation that's needed.
f(x) = -(9/4)x^2 The vertex form is usually defined as f(x) = a((x-h)^2)+k Where the sign of "a" (positive or negative) defines whether it opens up or down. "a" itself is it's aperture. The only points I could find from your graph (besides the origin) were (9,-4) and (-9,-4). The rule of correspondence would be -(9/4) which is basically taking the slope to the origin (difference in y / difference in x). "h" and "k" would be 0 for (h,k) is the vertex and the vertex is the origin (0,0). The image is too vague, but that's as close as you can get.
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