Question

how to integrate this?
x^(1/3)/[x^(1/3) -1] dx

Answer 1

let u = x^(1/3)-1
Therefore we can also say x^(1/3) = u+ 1 if we solve for it. Usuing these subs, I can rewrite our problem.
\[\int\limits_{}^{}\frac{ u+1 }{ u }=\int\limits_{}^{}1 + \int\limits_{}^{}\frac{ 1 }{ u } \]

Answer 2

ur da best, thank you ^_____^

Answer 3

Yep, np :3