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What is limit of x * ln(x) when x approaches 0. Please prove it.
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Someone answered x * ln(x) = ln(x) / (1 / x). Using L'Hospital I get that the limit is 0. Am I right?
Actually it should be \[\large \frac{x}{\frac{1}{\ln x}} \]Because this is an actual indeterminate form.
Look, since \(\ln(x)\) isn't defined for negative values, then the limit can't exist, right?
You can really only do a left hand limit. Is that your goal?
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