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Mathematics 18 Online
OpenStudy (anonymous):

What is the logarithmic function modeled by the following table...?

OpenStudy (anonymous):

x f(x) 9 2 27 3 81 4

OpenStudy (anonymous):

\[f(x)=\log _{x}^3\]

OpenStudy (anonymous):

\[f(x)=3\log _{10}^{x}\]

OpenStudy (anonymous):

\[f(x)=xlog _{10^{3}}\]

OpenStudy (anonymous):

OpenStudy (***[isuru]***):

Hi, the answer is \[f(x) = \log _{3}x\] Do u need explanation ?

OpenStudy (anonymous):

Kind of...

OpenStudy (anonymous):

I have a few more questions as well

OpenStudy (***[isuru]***):

so... do u know about the logarithmic rule... \[\log _{a }a = 1\]

OpenStudy (anonymous):

If Ken wanted to create a function that modeled a base of 11 and what exponents were needed to reach specific values, how would he set up his function? \[a. f(x)=11^x\] \[b. f(x)=11^x\] \[c. f(x)=\log _{11}^{x}\] \[d. f(x)=\log _{x}^{11}\]

OpenStudy (anonymous):

Yes I know the rule

OpenStudy (***[isuru]***):

soo... in ur problem ... they ask to get 2 as the result if u enter 9 for the function... if the function is.... \[f(x) = \log _{3}x\] then f(9) is....\[f(9) = \log _{3}9= \log _{3}3^{2}\] now there is an another logarithmic rule... \[\log _{a}a ^{x} = xlog _{a}a = x\] according to that u can write... \[\log _{3}3^{2} = 2\log _{3}3 = 2\] which will give u the result needed... did u get it ?

OpenStudy (***[isuru]***):

For ur second part ... my knowledge about exponents is not good enough.. so I suugest u to take the help of someone like @mathstudent55 , @ganeshie8 , @e.mccormick , @TuringTest

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