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Mathematics 23 Online
OpenStudy (anonymous):

GEOMETRY: Find the area of the shaded region.

OpenStudy (anonymous):

OpenStudy (anonymous):

i have an answer but im not sure :) just want to check, pls help me :)

OpenStudy (jdoe0001):

any measurements given? like radius or such?

OpenStudy (anonymous):

notice, the area of the sector minus the are of the right triangle gives you the area of the segment. the total area you desire is 2 times the area of the segment.

OpenStudy (anonymous):

@jdoe0001 it's in the picture, r =1 :)

OpenStudy (anonymous):

the radius is 1. so the area of the sector is pi/4, the area of the triangle is 1/2 and the area of the segment is pi/4 - 1/2 = (pi - 2)/4 and the total area would be ...

OpenStudy (anonymous):

oops the area of the sector is pi/2 so the area of the segment is (pi - 1)/2 and the total area is...

OpenStudy (anonymous):

ohh, so im wrong. haha my answer is pi/2 - 1

OpenStudy (anonymous):

well, uhm thanks btw! @pgpilot326 :)

OpenStudy (anonymous):

@pgpilot326 may i ask? :) so the area we're looking for is times two of the shaded part of this: ?

OpenStudy (anonymous):

you got it

OpenStudy (anonymous):

yeah so doubling (pi - 1)/2 is pi - 1.

OpenStudy (anonymous):

you got it right.

OpenStudy (anonymous):

@pgpilot326 why is sector pi/2? isnt it pi/4?

OpenStudy (anonymous):

r^2 * theta (in radians) is the area of a sector with central angle theta.

OpenStudy (anonymous):

Area of the Sector = 1/2 r squared (teta) right?

OpenStudy (anonymous):

oops, you're right... it's theta/2

OpenStudy (anonymous):

so it's pi/4 :)

OpenStudy (anonymous):

2 (pi/4 - 1/2) ** doubling the area from my second pic** pi/2 -1 :) !

OpenStudy (anonymous):

sorry, going too fast. so yeah, the original area of segment = pi/4 - 1/2 = (pi - 2)/4 and total area is (pi - 2)/2

OpenStudy (anonymous):

haha thanks again @pgpilot326 :)

OpenStudy (anonymous):

sorry 'bout that!

OpenStudy (anonymous):

yah it's ok :)

OpenStudy (anonymous):

just in case... http://www.mathsisfun.com/geometry/circle-sector-segment.html

OpenStudy (anonymous):

thanks!

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