Find an equation of the tangent line to the curve at the point (0, 0). y=sin(2 x) + (sin(2 x))^2
just need to take the derivative and define it at x=0, y=0
... well, thats for the slope of the line, the point is given already to develop the point slope format
it's fairly easy... just need to find the slope since the y intercept is 0.
I don't know how to find the derivative
you might want to review your material then
go ahead @amistre64 , you got this.
it should have trig functions covered
.. im assuming this doesnt need to be accomplished with "first principles" :)
trig functions, and the chain rule. Any of that sound familiar?
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