Find an equation of the tangent line to the curve at the point (0, 0). y=sin(2 x) + (sin(2 x))^2

Question

amistre64 · Answer

just need to take the derivative and define it at x=0, y=0

amistre64 · Answer

... well, thats for the slope of the line, the point is given already to develop the point slope format

anonymous · Answer

it's fairly easy... just need to find the slope since the y intercept is 0.

anonymous · Answer

I don't know how to find the derivative

amistre64 · Answer

you might want to review your material then

anonymous · Answer

go ahead @amistre64 , you got this.

amistre64 · Answer

it should have trig functions covered

amistre64 · Answer

.. im assuming this doesnt need to be accomplished with "first principles" :)

amistre64 · Answer

trig functions, and the chain rule.  Any of that sound familiar?