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Mathematics
OpenStudy (anonymous):

Find an equation of the tangent line to the curve at the point (0, 0). y=sin(2 x) + (sin(2 x))^2

OpenStudy (amistre64):

just need to take the derivative and define it at x=0, y=0

OpenStudy (amistre64):

... well, thats for the slope of the line, the point is given already to develop the point slope format

OpenStudy (anonymous):

it's fairly easy... just need to find the slope since the y intercept is 0.

OpenStudy (anonymous):

I don't know how to find the derivative

OpenStudy (amistre64):

you might want to review your material then

OpenStudy (anonymous):

go ahead @amistre64 , you got this.

OpenStudy (amistre64):

it should have trig functions covered

OpenStudy (amistre64):

.. im assuming this doesnt need to be accomplished with "first principles" :)

OpenStudy (amistre64):

trig functions, and the chain rule. Any of that sound familiar?

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