Question

Find an equation of the tangent line to the curve at the point (0, 0). y=sin(2 x) + (sin(2 x))^2

Answer 1

just need to take the derivative and define it at x=0, y=0

Answer 2

... well, thats for the slope of the line, the point is given already to develop the point slope format

Answer 3

it's fairly easy... just need to find the slope since the y intercept is 0.

Answer 4

I don't know how to find the derivative

Answer 5

you might want to review your material then

Answer 6

go ahead @amistre64 , you got this.

Answer 7

it should have trig functions covered

Answer 8

.. im assuming this doesnt need to be accomplished with "first principles" :)

Answer 9

trig functions, and the chain rule. Any of that sound familiar?