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Stupid Question... whats the vertex of y=x^2? Is it 0,0?
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yes
whats the vertex of -2(x+3)^2+1 @Data_LG2
y=a(x-h)^2+k --> (h,k) are the coordinates of the vertex
so 0,3
oh! 3,1
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Correct?
which graph would open down? 0,0 or 3,1?
if the value of a is negative then it's open down, if a is positive it's open up
y=x^2 y=-2(x+3)^2+1 which one opens down and which one is more narrow? So the narrow is y=x^2 and opens down is -2(x+3)^2+1
-2(x+3)^2+1 is more narrow
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thanks Data
XD lol you already figure it out all by yourself... k gtg
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