Question

Find the equation for the horizontal tangents to the curve y=x^3-3x-2

Answer 1

take the derivative, set it equal to zero, and solve for \(x\)

Answer 2

clear or no?

Answer 3

i am going to take that as a "no"
the derivative is \(3x^2-3\)
et it equal to zero and solve for \(x\) i.e. solve
\[3x^2-3=0\] or even \(x^2-1=0\)

Answer 4

sorry I was working on the other parts of this problem. How did you find the derivative?

Answer 5

Ok forget it, I figured it out. Thanks.

Answer 6

So the tangents are x=1 and x= -1?

Answer 7

No it's just 1.