Question

Trying to find the x and y intercepts of

x=3y^2-7

Answer 1

Set x equal to 0 to solve for the y intercept. Set y equal to 0 for the x-intercept. Can you take it from there?

Answer 2

I set y = to 0 and get

x=-4

so the X intercept is (0,-4)?

Answer 3

How exactly did you get -4? Can you show me what you substituted?

Answer 4

x=3(0)^2-7
ah but its -7

so X intercept is (-7,0)?

Answer 5

Exactly.

Answer 6

o know the Y intercept is the one I am really having trouble with because when working it I I have the square and a fraction

Answer 7

Okay.
x=3y^2-7
0=3y^2-7
7=3y^2
7/3=y^2
\[\pm \sqrt{\frac{ 7 }{ 3 }}\]

Answer 8

Do you need me to explain the process, or are you fine with that?

Answer 9

I did get that. I typed it in before had into my homework and got it wrong. I typed:

(0,-7/3)(0,7/3)

Answer 10

huh. No clue.

Answer 11

Have you tried reversing the answers (negative before the positive coordinates)?

Answer 12

yes