Question

find the tangents of the following curves x^2 + 16y^2 = 32 from (-6, 7/2). the answers are x+4y -8 and 41x + 4y + 232

Answer 1

(-6, 7/2)

Answer 2

IF YOU are having a tangent then consider 1st point a,b and slope of it from (-6,7/2) will be equal to to slope of parabola at that point... since its a parabola then you will get two line..

Answer 3

okay thanks!!!

Answer 4

no prob.. (:

Answer 5

i don't think this is a parabola

Answer 6

\[ x^2 + 16y^2 = 32\]
\[2x+32yy'=0\]
\[y'=-\frac{x}{16y}\]