Question

How many grams of Sodium carbonate (Na2CO3) contain 1.773x10^17 carbon atoms?

Answer 1

HOw do i solve this?

Answer 2

1 mole of sodium carbonate = 106 g ..As sodium carbonate contain 1 carbon atom = 6.022 x 10 ^ 23 so 1.773 x 10 ^17/ 6.022 x 10 ^23 = ur answer

Answer 3

Na2CO3
m= ?
N =1.773 x 10^17

First, you need to find moles using the N (number of carbon atoms) and Avogadro's number (6.022 x 10^23) and this formula:

n= N / NA

Using the moles, you can figure out mass by multiplying the moles by the molar mass of the compound.

Ta da.