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f(x)=1-x/3x+2. Find f^-1(x)
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\[x=\frac{1-y}{3y+2}\] solve for \(y\) it takes a few steps
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1) multiply both sides by \(3y+2\) to get \[x(3y+2)=1-y\]
2) distribute on the left to get \[3xy+2x=1-y\]
3) put all terms with \(y\) on one side, all else on the other \[3xy+y=1-2x\]
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4) factor out the \(y\) on the left \[(3x+1)y=1-2x\]
5) divide both sides by \(3x+1\) \[y=\frac{1-2x}{3x+1}\]
6) write \[f^{-1}(x)=\frac{1-2x}{3x+1}\]
THANKS!
it was a lot of steps check my algebra, but i think it is right yw
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It's correct.
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