Question

please help? RADICAL EQUATIONS

Answer 1

\[\sqrt{x-96} + 9 = 29\]

Answer 2

-9 both sides
square both sides
done.

Answer 3

\[\sqrt{x-96} = 29-9\]
\[\sqrt{x-9} = 20\]
\[(\sqrt{x-96})^{2} = (20)^{2}\]
\[x-96 = 400\]
\[x=400+96\]
\[x=304\]

Answer 4

easy, right?

Answer 5

but the last line seems odd

Answer 6

496

Answer 7

That's better.

Answer 8

lol agree with mathstudent55

Answer 9

and now to check it please let me know if im right...

Answer 10

I am praying, "Please, God, let it correct"

Answer 11

@henryarias5
Just a quick note on radical eqiuations:
When you square both sides of an equation, you may be introduing extraneous solutions. These are solutions that work on the squared equation but do not work on the original equation. Therefore, anytime you square both sides of an equation, you must check every solution in the original equation.

Answer 12

\[\sqrt{x-96} + 9 = 29\]
\[\sqrt{496-96} + 9 = 29\]
\[\sqrt{592} + 9 = 29\]
wait, so thats an extraneous solution?

Answer 13

The solution x = 496 is correct.
Your check is incorrect.
496 - 96 = 400, not 592.

Answer 14

ok then it would be

Answer 15

\[\sqrt{400} +9 = 29\]
\[20 + 9 = 29\]
\[29 = 29\]
NO EXTRANEOUS

right?

Answer 16

Correct.