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limit (1+(1/x^2))x as x approaches infinity
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using L'Hopitals rule
This?\[ \lim_{x\to\infty}\left(1+\frac{1}{x^2}\right)x \]
yes
I know the answer is infinity but I need to know how to do it with L'Hopital
So simplify the inner part a bit: \[ \left(1+\frac{1}{x^2}\right)x=\frac{x^2+1}{x} \]
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Divide everything by \(x\): \[ \frac{x+\frac 1x}{1} \]
so its 2x/1 and then you get infinity
You don't need to use l'Hospitals rule on this one.
This goes to infinity and it isn't an indeterminate form.
yeah I know but I need to do it with L'Hopital
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Okay, well you know how to do derivatives, I don't see the issue.
okay I just couldnt figure out how to get it in a form where I could do it in the end it was obvious lol. Thanks for the help.
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