Determine the number of real solutions of -2x^2 + 5x - 3 = 0. A. 0 B. 1 (double root) C. 2
NOt sure how to do this
What is the discriminant?
ax^+bx+c
Attached are two charts to help you think about this type problem.
ax^2*
ax^2+bx+c is not the discriminant. Read about the discriminant on the attachment above.
b^2-4ac
ok let me try that
is it B
I got 1 for the discriminant but that does not mean that there is a double root.
Ok.
Look at the chart above with the title discriminant and root types. Under the discriminant column, find the description that fits the type number 1 is and read across the chart and look at the root description. Do that now, please. @Reaper534
2 irrational roots?
Wait 1 is a perfect square right so it would be 2 rational roots right?
\[-2x^2 + 5x - 3 = 0.\]easier to solve \[2x^2-5x+3=0\] use the quadratic formula
@satellite73 i got -6 and 6.5
-6.5*
i don't think that is right
this one factors as \[2x^2-5x+3=(2x-3)(x-1)\]
@satellite73 would it be equal to zero?
like (2x-3)(x+1)=0
@Reaper534 >>>Wait 1 is a perfect square right so it would be 2 rational roots right? Correct
Thanks! So its C correct?
@Directrix
C) 2 is correct @Reaper534
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