Question

partial derivative - az/ax z=arctan(y/x)

Answer 1

hi

Answer 2

i know tan-1 is 1/1+x^(2)

Answer 3

so it's 1/1+[(y/x)]^2*something right?

Answer 4

I can't even read the thing typed.

Answer 5

what?

Answer 6

so question is partial az/ax z=arctan(y/x)

Answer 7

what does az/ax mean?

Answer 8

partial derivative of arctan with respect to x?

Answer 9

partial z / partial x

Answer 10

'a' this isn't an alphabet a

Answer 11

it's symbol of partial

Answer 12

Try `\(\partial\)` \(\partial\)

Answer 13

\(\partial\)z/\(\partial\)x z=\[\tan^{-1} (y/x)\]

Answer 14

\(\partial\)z/\(\partial\)x z=\[\tan^{-1} (y/x)\]

Answer 15

Okay so use chain rule.

Answer 16

\[
\frac{\partial }{\partial x}\tan^{-1}\left(\frac yx\right) = \frac {-\frac{y}{x^2}}{\left(\frac yx\right)^2+1}
\]

Answer 17

That what I get when using chain rule.