Question

Find an equation of the circle that has center (-3,2) and passes through (4,-6) .

Answer 1

(x -h)^2 + (y - k)^2 =r^2
^equation of a circle. plug things in.

Answer 2

(h,k) being the center

Answer 3

equation of a circle is: \[(x-h)^{2}+(y-k)^{2}=r^{2}\]
(h,k) is the center
substitute (x,y) to find r
rewrite equation

Answer 4

i do that and come to sort(113)

Answer 5

sqrt*

Answer 6

r=sqrt113?

Answer 7

yep

Answer 8

and my equation would be (x--3)+(y-2)=113

Answer 9

Don't forget the squared part in the left side (Refer to the standard equation I wrote above) you can leave 113 as it is though since it is already squared.

Answer 10

i see, thanks team

Answer 11

(4+3)^(2)+(-6-2)^(2)=r^2

49+64=r^2

113=r^2

equation would be

(x+3)^(2)+(y-2)^(2)=113

so yes you had it right:)

Answer 12

woot thanks! <3