Question

Find the number of real solutions of the quadratic equation with: a = -1, b = 1, c = -9.
A. no real solutions
B. 1 real solution
C. 2 real solutions
D. 3 real solutions

Answer 1

When the general form is,
\[ax^{2}+bx+c\]
Your equation would be
\[-x^{2}+x-9\]
now foil, or use the quadratic formula to find answer

Answer 2

Part of the quadratic formula is
square root of b² -4 * a * c
since you are looking for a square root if
b² -4 * a * c > 0 equation has 2 real roots
if b² -4 * a * c < 0 equation has no real roots
Calculate b² -4 * a * c and you'll have your answer.

Answer 3

C.

Answer 4

@AntoinetteWillman What did you get for the discriminant? What number?

Answer 5

>>C.

I did not get that option as being correct.

Answer 6

Okay.

Answer 7

I am waiting for you to crank out the discriminant but it appears that is not happening.

So, will you crank this out: (1)² - 4(-1)(-9) = ? @AntoinetteWillman

And, post what you get, okay?