Question

Solve the equation:

25x^2 -24x-9=-7x^2 +12x-18

Answer 1

What's the problem? Any ideas?

Answer 2

um i made it equal to zero but idk how to factor it because i got 32x^2 -36x+9=0
i dont know what to do now....

Answer 3

This one's a bit difficult to factorise, but think about two numbers that multiplied to get 32. Also think about another two numbers multiplied to get 9.

Answer 4

i did think but i dont know what it is can u please show me step by step?

Answer 5

For 32, you got (8 times 4) you get 32.
For 9, try (3 times 3) you get 9.

Now we have 8 and 4, 3 and 3

(8x ? 3)(4x ? 3)=0
The missing slot there is where you either put in + or - depends on the middle value, which we have there is -36x.

Distributing that,
So 8x times 3 is 24x
3 times 4x is 12x

To get -36x, both 24x and 12x must be negative, so which means

(8x - 3)(4x - 3)=0

Answer 6

okay i have another question..
it says find the zeroes of the function by rewriting the function in intercept form.
y=3x^2 +2x

Answer 7

Finding zeroes means letting y=0
3x^2 +2x=0
x(3x+2)=0

x=0, x=-2/3

Answer 8

wait no whyd u delete it? i need the work on that one

Answer 9

I copied the problem incorrectly. I think Sam is correct.

Answer 10

I'll rework the problem.

Answer 11

okay i have another question...

find wheter the graph has a maximum or minimum value find the value..

y= (x-6)^2+3

Answer 12

32x^2-36x+9=0
(8x-3)(4x-3)=0

x= 3/8 or x= 3/4

Answer 13

no its graphing read the question

Answer 14

y= (x-6)^2+3

When I graphed, your have a minimum (6,3)

You can find a free graphing calc at http://www.meta-calculator.com/online/

Answer 15

25x^2-24x-9=-7x^2+12x-18
(25x^2+7x^2)+(-24x-12x)+(-9+18)=0
32x^2-36x+9=0
x^2-36/32x+9/36=0
x^2-9/8x+1/4=0
x^2-81/256+81/256-9/8x+1/4=0
x^2-9/8x+81/256+(1/4-81/256)=0
(x-9/16)^2=81/256-1/4
x-9/16=sqrt(81/256-1/4)
x=sqrt(81/256-1/4)+9/16

Answer 16

For
y= (x-6)^2+3,
y= (x-a)^2+b

Vertex of the graph is (a,b), so the vertex is (6,3)
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When you expand this (x-6)^2+3 , you should get positive coefficient for x^2, that means the graph should be a minimum graph/ curve upwards.

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You could also find out where the y-intercept is by setting 'x' = 0, the y-intercept should be
39.

y=(x-6)^2+3
y=(-6)^2+3
y=36+3
y=39