Question

The quotient of a number and 2 is the same as the difference of the number doubled and 3.
@Hero
so...I just want to check if im right...

Answer 1

\[N \div 2 = N^2-3\]

Answer 2

I think "number doubled" means 2xN

Answer 3

>_> a number doubled is a number times it self...

Answer 4

If I double 50 I think it is 100 and not 50 x 50. We can wait for someone else to clarify this matter.

Answer 5

ahh it is...my bad...Major brain fart...

Answer 6

So N/2 = 2N - 3
N = 4N - 6
6 = 3N
N = 2

Answer 7

\[N \div 2 = N timesN - 3\]

Answer 8

Pfft...stuipid thing...

Answer 9

\[N \div 2 = N \times N - 3\]

Answer 10

On the right it should be 2 x N and not N x N

Answer 11

DAMNIT i did it again!

Answer 12

\[N \div 2 = N \times 2 - 3\]

Answer 13

Yes. See a few replies above for solution. N = 2

Answer 14

The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers.
Ok...so... for this one i would need to take... wait what?!

Answer 15

\(\dfrac{n}{2} = 2n - 3\)
\(n = 2(2n - 3)\)
\(n = 4n - 6\)
\(6 = 4n - n\)
\(6 = 3n\)
\(2 = n\)

Answer 16

The first number is \(n\)
The second (larger) number is \(n + 1\)

\(n + 1 = 2n + 7\)

Answer 17

Gah...idk...ill never pass math D:

Answer 18

I know it's the "greater than" part that is throwing you off. The mean 7 "more than" rather than using the greater than symbol \(>\)

Answer 19

*just sobs*

Answer 20

By the way, in general, if \(n\) is the first number, then \(n + 1\) is the consecutive number.

Answer 21

or the second number.

Answer 22

You have to use your own judgment to figure out if they want you to add the seven or use the greater than symbol.

Answer 23

I'm sorry. Word problems can ruin people's lives.

Answer 24

*just quite sobbing*

Answer 25

so...what would the awnser be... *sobs*
The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers.


4, 5
-8, -9
-5, -6
-6, -7

Answer 26

Just solve the equation.

Answer 27

You need to find \(n\) and \(n + 1\)

Answer 28

Waaa? ok...so...how do i start...

Answer 29

Basically you take this equation:
\(n + 1 = 2n + 7\)
and you solve for \(n\)

Whatever result you get, add 1 to it. Then you will have \(n\) and \(n + 1\)

Answer 30

I dont know how to solve it...its...to...IDK...it doesnt make sense when i look at it...how would i go a bout findning in?

Answer 31

\(n + 1 = 2n + 7\)
\(1 - 7 = 2n - n\)
\(-6 = n\)
\(-6 + 1 = n + 1\)

Answer 32

So...>_> -5?

Answer 33

\(n = -6\)
\(n + 1 = -5\)

Answer 34

*sobs quitely and hugs hero* Thank you D:

Answer 35

yw