restriction of (x^2+3x+2)/(x^2-2x-3) * (x^2+4x+3)/(x+2)
x ≠ -3 x ≠ 3 x ≠ 1 x ≠ -2 I'm getting different results so I'm lost.. I'm getting a result of x plus or minus -1, -2 and 3
\(\left(\dfrac{x^2 + 3x + 2}{x^2 - 2x - 3}\right) \left(\dfrac{x^2 + 4x + 3}{x + 2}\right)\)
Yes....
Now...without doing any work at all, what can x not equal?
We know that \(x + 2 \ne 0\) right?
mhm
So what can x not equal?
I understand the extra help but I just need to know which of my results are correct... I'm getting two that match my answer choices but I can only click one
It's not giving a direct answer imo since I've done the work already
that's what I have marked, thanks.
Nah, I said only I can pick one
Well, factors of one can cancel...so maybe we should try to factor this one.
Huh...? I said I can only pick one answer which is -2 o.o
\(\left(\dfrac{(x+2)(x+1)}{(x-3)(x+1)}\right) \left(\dfrac{(x+3)(x+1)}{x + 2}\right)\) Yes, I know, however, if factors can cancel, then we'll be able to reduce it to just one answer choice.
\(\left(\dfrac{\cancel{(x+2)}\cancel{(x+1)}}{(x-3)\cancel{(x+1)}}\right) \left(\dfrac{(x+3)(x+1)}{\cancel{x + 2}}\right)\)
Now we're left with just: \(\dfrac{(x+3)(x+1)}{x-3}\)
So \(x - 3 \ne 0\) and \(x \ne 3\)
Well... How did I get -1 then? o_o does that mean it's changed to 3 and not -2?
Since factors of one cancel, we can reduce the fraction to a simplified form and find what x definitely cannot equal.
so.. x cannot equal -2 and 3? it looks that way due to how you wrote it (I have another question like this)
Sorry, but if we can cancel factors, then they are no longer restrictions. \(x \ne 3\) is the correct choice.
I suppose that makes sense :O the other one is (5x^2-10x-15)/(x^2-9) divided by (6x+12)/(x+2) I've gotten multiple results as well. choices are: x ≠ -2 x ≠ -3 x ≠ 3 x ≠ 9
is it B, -3?
You basically do the same thing as before which is reduce it to simplest form first, then figure out the restriction.
@whalexnuker show your work
I see you typing- I got it, thanks ;o
What do you mean, you got it? What work did you do to get it?
I got the answer.. I submitted the test and got full credit o.o that's why the question was closed earlier. I just haven't strayed from the question, lol
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