Question

1 + sec2x sin2x = sec2x
Proving trigonometric equations

Answer 1

are you sure the question is correct ?
its sec4x and not \(\sec^4x\)

Answer 2

so, the question really is
\(\large 1+\sec^4x\sin^2x=\sec^2x\)
? yes/no ?

Answer 3

yes

Answer 4

col, so
lets start by using
sec x = 1/cos x
plug this into your equation, what u get ?

Answer 5

can u ?

Answer 6

uhm no

Answer 7

\(1+\sin^2x/\cos^4x= (\cos^4x+\sin^2x)/\cos^4x\)

Answer 8

ok

Answer 9

wait it's 1+sec^2x not 1+sin^2x

Answer 10

oh, that is why i was thinking why i was not able to solve...
so, its
\(\large 1+\sec^2x\sin^2x=\sec^2x\)
?


this is really simple...

Answer 11

yeah

Answer 12

put sec x = 1/cosx
and use sin^2x + cos^2x =1

Answer 13

thanks