Question

If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', would the ordered pair of X' be (-4,5)?

Answer 1

y = 1 is a horizontal line

Answer 2

when u reflect anything over horizontal line, its x-coordinate will not change

Answer 3

so, X' will be (4, something)

Answer 4

@ganeshie8 (4, -5)?

Answer 5

Since you are reflecting about y=1, as @ganeshie8 said, the x coordinate won't change. The y coordinate will the SAME DISTANCE from y=1 as in the original point, but on the OTHER SIDE of the line y=1.

It's like you put a mirror down where the line y=1 is, so everything is just "flipped" over that line.

So where does the new point end up, vertically speaking? What is the y-coordinate that is the SAME DISTANCE from y=1, but on the opposite side of the line y=1?

Answer 6

(By the way, (4, -5) would be a reflection of the point over the x-axis. Notice that y=-5 is the same distance from the x-axis that y=5 is, but on the other side.)

Answer 7

See graph

Answer 8

to figure out where X' is, count how many steps up from y=1 to the point X
then count down from y=1 the same number of steps to get to X'

Answer 9

@phi so it would be (4,-3)?

Answer 10

\(\large \color{red}{\checkmark}\)

Answer 11

yes