Question

Check my answer to see if I'm right?

Answer 1

What are the zero(s) of the function f(x)=(5x^2-25x)/(x)

Answer 2

I said x = 0 and x = -5

Answer 3

Well. I will tell you that there is only one zero. This problem contains a special case; it is not a quadratic function. Can you rationalize the fraction by crossing out x's for me
?

Answer 4

\[\frac{ 5x^{2}-25x }{ x }\] Notice that you can factor out an x in the numerator by \[\frac{ x(5x-25) }{ x }\] here you can cross out the x on the denoimator and the numerator leaving you with
5x-25=y... Set this equal to zero and solve and you will have your answer.
I hope this did help!

Answer 5

so im right? o.o

Answer 6

haha. ehh not really.
Ok so the zero of a graph is where the graph of the line touches the x axis... So that is at where y=0... So we set the fraction equation equal to zero after we rationalized it. Do you understand how I rationalized it/factored it?

If so just solve for x in 5x-25=0 and you have your answer.

Answer 7

It's just 0? D:

Answer 8

To Solve:
5x-25=0
add 25 to both sides
5x=25
divide by 5
x=5
Does this make sense?

Answer 9

Zero, 0, is not a root for this @Gerardo_cast23 has it explained the root is only 5 because the x on the numerator got factored and canceled with the x on the denominator.

Answer 10

Its not a quad eq :)

Answer 11

@.Sam. So what's the answer...? It's not x=5.
x = -5
x = 0 and x = -5
x = 0

Answer 12

The answer is x=5

Answer 13

It cann't beeee. My test said that's wrong.

Answer 14

Can't be

Answer 15

http://i1341.photobucket.com/albums/o749/whalexnuker/untitled_zps8afe47d6.png
xD This test is stupid.

Answer 16

Stupid question -.-

Answer 17

I know, wolfy told me the same (that is wolfy) :c perhaps it's asking for something more..?

Answer 18

Hmm I don't think so @hartnn

Answer 19

x=5 must be correct...

Answer 20

Yeah

Answer 21

let me call my teacher lmao.

Answer 22

x=-5

Answer 23

I knew it had to be -5 due to the "-25x". The square root of -25 is -5

Answer 24

what sort of logic is that!?
is that your teacher's logic ?:P

Answer 25

yeah XD he told me it was -5. since X can't be 0, that eliminates B and C
and since I already chose D and that was wrong... it left me with a, x=-5

Answer 26

OH.MY.GOD!

Answer 27

i shall bow in front of your teacher....

Answer 28

I bet you just had a duh moment? XD

Answer 29

I'm off, have fun :)

Answer 30

lol, what ? duh moment ?

tell your teacher, x=5 is correct, and not x=-5

Answer 31

want me to prove it ?
when x=5
5x^2 -25x = 5*25-25*5 = 125-125 = 0
which means f(x) has a zero at x=5
and not -5