If you save one penny on January 1, two pennies on January 2, three pennies on January 3, and continue this pattern for one year (not a leap year), what will be the value of your entire savings, in dollars, at the end of that one year? Express your answer as a decimal.
I think you know the answer...........you just don't know the number right?
The answer is Total money (in pennies) = 1+2 +3 +4+..........................+364+365 right
Yes
What equation would i use to figure this out?
I think this involves the 365! equation...just keep adding :P
That's a lot of adding though! D:
You can do this with Gaussian addition http://mathcentral.uregina.ca/QQ/database/QQ.02.06/jo1.html, or do it as an arithmetic sequence
Have you learned arithmetic sequences...?
Yes, I've learned about them. I just didn't remember which formula to use. I will try the Gaussian addition though.
It's 66,795 pennies, now you just have to decide how many dollars thats worth :)
sry I was away: let Total Amount be S So S = 1+2+3+................................+364+365 now reverse it S = 365 +364 +..............................+2+1 Add them up and see........you don't need any formula for this :0
If you use arithmetic sequences, you'll get the gaussian addition formula anyway
Add S forward and S reverse
its 66795 pennies, move the decimal place voer 2 and you get 667.95 dollars.
I used the Gaussian addition formula and I got 66,795 pennies. So I guess $667.95 is the answer?
yes tegiebear :D
Okay, thank you guys very much! :)
S = 1 + 2 + 3 + 4 +.....................................364 + 365 S =365+ 364+ 363+362+.........................................2 + 1 Adding 2S = 366 + 366 + 366 +...................365 times 2S = 365*366 S = 365*366/2 Thought this trick will help you
@atlas the link i first posted shows that exact method (Gaussian addition)
ah sry i didn't see it............... :P
no prob, plus it was only using 1 to 100 not 1 to 365
oic
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