Find the constant of variation for the quadratic variation.

6y = 4x2

A.

3/2

B.

2/3

C.
–2

D.

4/9

Question

Find the constant of variation for the quadratic variation.
 
    6y = 4x2
 
 A.
 
 3/2 
 
 B.
 
 2/3  
 
 C.
–2
 
 D.
 
 4/9

mathstudent55 · Answer

For the quadratic variation shown below,
$y = kx^2$,
the constant of variation is $k$.

Solve your equation for y.

anonymous · Answer

How can you explain?

mathstudent55 · Answer

Direct variation is
$y = kx$, with constant of variation $k$.

Quadratic variation is 
$y = kx^2$, with constant of variation $k$.

You have quadratic variation 
$6y = 4x^2$
If you solve it for y, you will have it in 
$y = kx^2$ form, and the number that multiplies x is the constant of variation.

anonymous · Answer

So what do I do with the 6

mathstudent55 · Answer

Since y is being multiplied by 6 and you want y by itself, divide both sides by 6.

anonymous · Answer

ISn't the other gonna be 4x^2/6

anonymous · Answer

@mathstudent55

mathstudent55 · Answer

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