Question

What is the minimum value for z=3x-1/2y over the feasibility region defined by the constraints shown above?

Answer 1

Choices:
-4
-5
-3
-6

Answer 2

@DSS
Do you know how to do this? This is my last question.

Answer 3

x should be small and y should be big. this makes it easy for us, because the upper bound for y, which we want, is the same for all possible x values.

so we pick the minimum possible x-value (0) and the biggest possible y-value (8) and this gives us the minimum value z = 0*x - 1/2*8 = -4.