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Mathematics 8 Online
OpenStudy (loser66):

I am confused, please explain me. \[R^2\text { is a subspace of }~R^3 \]??

OpenStudy (loser66):

@dan815

OpenStudy (dan815):

any line that passes through the origin is a subspace of r3

OpenStudy (loser66):

I am with you but the book says no. that's why.

OpenStudy (dan815):

not all r2 is

OpenStudy (dan815):

only the lines that pass through the origin

OpenStudy (dan815):

only if the line has has a linear combination that equal 0 without the linear combination coefficient being 0

OpenStudy (loser66):

so, the subspace of R^2 which contains all of lines through origin is a subspace of R^3, not the whole R^2, right?

OpenStudy (dan815):

yes

OpenStudy (loser66):

ok, thanks a lot, friend

OpenStudy (dan815):

because if you have a line in r3 that doesnt pass trhough the origin then yhou can have a linear combination that leaves the origin, or just multplying by zero u know u are not on that r2 space anymore

OpenStudy (dan815):

there is no subspace that exists without containting the origin

OpenStudy (loser66):

one more question, dan?

OpenStudy (dan815):

okay i will asnwer after ,i have to go pick up my brother

OpenStudy (loser66):

I am waiting until then to ask, signal me then,ok?

OpenStudy (dan815):

oh and umm r2 is a plane i mean a plane that passes throug hte origin!! okay brb

OpenStudy (loser66):

if m<n, then any spanning set of R^n must contain more vectors than any spanning set for R^m, true, false?

OpenStudy (dan815):

try to vizualize it u can do it

OpenStudy (dan815):

if u mean linearly dependant vectors then false but not linearly dependant u can have infinite vectors but they will be redundant

OpenStudy (dan815):

for example to define a point in r2 space a plane if you use 2 well defined vectors that are orthogonal, u can go through any point in that r2 space but, u can also go throught that point with 3 vectors or addition of 4 vectors and so on..

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