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So, I'm doing Arc Length formula - I found the derivative of x^(3/2) = 9x/4, now I have sqrt(1+(9x/4)) - how do I rid of the sqrt without a perfect square?
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i'm guessing you meant the derivative squared was 9x/4\[\Large \frac{ d }{ dx } x^{3/2} = \frac{ 3 x^{1/2} }{ 2 }\] \[\Large \int\limits_{a}^{b} \sqrt{1 + \frac{ 9x }{ 4 }} dx\]use substitution - let u=1+9x/4
du/dx = 9/4
\[4/9\int\limits_{4}^{5}\sqrt(U)du\]?
If I use a u-sub then I have to include the "du" - am I wrong?
That's all correct so far, good job. Just integrate it.
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Webassign is super picky with it's answers, but I got it! thank you!
No prob.
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