Question

What is the equation of a parabola with a vertex at (0, 0) and a focus at (0, 6)

Answer 1

do you know what it looks like approximately?

Answer 2

not at all.

Answer 3

well that was wrong lets try again

Answer 4

i know what the graph looks like. i meant i didn't know what the equation looks like. haha

Answer 5

vertex is at the origin \((0,0)\) and focus is at \((0,6)\)which is 6 units up
we need to know what it looks like so we know that the \(x\) term is squared, i.e. it the equation will look like
\[4py=x^2\]

Answer 6

and in your case \(p=6\) so you get
\[24y=x^2\]

Answer 7

now i have to break down the x^2 to be x =

Answer 8

well no, there is no breaking down \(x^2\) whatever that means
you cannot write this as \(x=\text{ something }\)

Answer 9

are you sure? okay.

Answer 10

i am sure
the \(x\) is squared, it is \(x^2\) not \(x\)

Answer 11

lets check it
http://www.wolframalpha.com/input/?i=parabola+24y%3Dx^2