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19.0 grams of barium hydroxide is dissolved in 184 ml of water (no vol. change). how many ml of .800 M of HCl would be needed to completely neutralize 15.16 ml of the barium solution?
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Should be 19.20 grams of barium hydroxide
Write the balanced equation.
Ba(OH)2 + 2HCl = BaCl2 + 2H2O
The balanced equation says that 1 mole of barium hydroxide is neutralized by 2 moles of hydrochloric acid. So how many moles of barium hydroxide are you trying to neutralize?
Whatever the 19.20 grams of the solution works out to be which is around 0.112 moles i believe
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So, assuming that is correct, you need .224 moles HCl. The solution you are using has .8 moles per liter. How many liters would you need to give you .224 moles?
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