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cosθ=2/3 and sinθ>0,find cotθ
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Since both sine and cosine are positive, it must be in the first quadrant.
thanks I agree but what would cotθ be?
You need to find \(\sin(\theta)\) first.
Use \[ \cos^2\theta + \sin^2\theta = 1 \]
cos^ θ+sin^2 θ=1 is the formula but I'm lost.
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Well you know \(\cos \theta = 2/3\) so plug that in.
\[ \frac 49+\sin^2\theta = 1 \]
Find \(\sin \theta\) and remember that \(\cot\theta = \cos\theta/\sin\theta\)
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