2nd question) Need to calculate rate of change of length of square whose area equal to 100m2, where rate of change dAdt=1m2s
\[\frac{ dA }{ dt }=1 \frac{ m ^{2} }{ s }\]
Need to find rate of change of this square's length
Okay so remember the chain rule: \[ \frac{dA}{dt}=\frac{dA}{dx}\frac{dx}{dt} \]Where \(x\) is the length of a side in this case.
"rate of change of length of square" This means they want us to find: \[ \frac{dx}{dt} \]
So first of all, can you dentify what \(dA/dx\) is?
Consider what \(A(x)\) is first.
A=L^2
Well, \(x\) not \(L\) in this case.
So what is \[ \frac{dA}{dx} \]?
i dont know, what can be x?
Well, we know \[ A=100m^2 \]And \[ A=x^2 \]
\[\frac{ dA }{ dx }=\frac{ dx ^{2} }{ dx }=2x\]
Right!
so 20m/s is the answer?
\[ 1\frac{m^2}{s}=2(10m)\frac{dx}{dt} \]
It's not \(20mx/\)
1/20?
Yes.
damn it), i made a mistake, thx for a second time :D
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