y=-(x-1)(x+4)

Question

y=-(x-1)(x+4)

ammarah · Answer

@ganeshie8

ganeshie8 · Answer

put $\large x = -\frac{3}{2}$

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

ammarah · Answer

ok this exactly the part where im stuck attt

ganeshie8 · Answer

i hate negatives, so i factor out -1 from first bracs so that it cancels out wid outer -

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1)(-\frac{3}{2}+4)$

ganeshie8 · Answer

fine so far ? :)

ammarah · Answer

yes

ganeshie8 · Answer

Next, i see that I am dealing wid fractions.
so i better make denominators common, so i can add them

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1 \times \frac{2}{2})(-\frac{3}{2}+4 \times \frac{2}{2})$

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1 \times \frac{2}{2})(-\frac{3}{2}+4 \times \frac{2}{2})$

$\large  y=(\frac{3}{2}+\frac{2}{2})(-\frac{3}{2}+\frac{8}{2})$

ganeshie8 · Answer

Now that denominators are common.
I can add the tops

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1 \times \frac{2}{2})(-\frac{3}{2}+4 \times \frac{2}{2})$

$\large  y=(\frac{3}{2}+\frac{2}{2})(-\frac{3}{2}+\frac{8}{2})$

$\large  y=(\frac{3+2}{2})(\frac{-3+8}{2})$

ganeshie8 · Answer

simplify

ammarah · Answer

so its 5/2*5/2

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1 \times \frac{2}{2})(-\frac{3}{2}+4 \times \frac{2}{2})$

$\large  y=(\frac{3}{2}+\frac{2}{2})(-\frac{3}{2}+\frac{8}{2})$

$\large  y=(\frac{3+2}{2})(\frac{-3+8}{2})$

$\large  y=(\frac{5}{2})(\frac{5}{2})$

ganeshie8 · Answer

yes,

ammarah · Answer

25/2

ganeshie8 · Answer

$\large y=-(x-1)(x+4)$

$\large  y=-(-\frac{3}{2}-1)(-\frac{3}{2}+4)$

$\large  y=--1(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1)(-\frac{3}{2}+4)$

$\large  y=(\frac{3}{2}+1 \times \frac{2}{2})(-\frac{3}{2}+4 \times \frac{2}{2})$

$\large  y=(\frac{3}{2}+\frac{2}{2})(-\frac{3}{2}+\frac{8}{2})$

$\large  y=(\frac{3+2}{2})(\frac{-3+8}{2})$

$\large  y=(\frac{5}{2})(\frac{5}{2})$

$\large  y=\frac{25}{4}$

ammarah · Answer

oh yeahhh

ganeshie8 · Answer

when u multiply two fractions,
u multiply tops together
u multiply bottoms together

ammarah · Answer

yes