Why is integral of y = x^2 + b , 1/3 x^3 + b but integral of y = x + b is 1/2 x^2 + x ? sorry if my question is simple or incorrect :) i'm new at calculus :)
is b a constant?
yes :)
Hey... uhh \[\Large \int (x^2+b)dx = \frac13x^3 + bx \color{orange}{+C}\]
Wrong emphasis.. I should have emphasised the bx part.
sorry i don't understand :)
Well the integral of a constant is just THAT constant times x. So the integral of the b part is bx, not simply b.
take the derivative of your answer if it doesnt give you what you integrated then you did it wrong
Actually^ LOL
Im so rusty with integrals blah I need to relearn them they are a lot of fun
so my question is wrong?
what is the derivative of 1/3 x^3 + b
also you didnt include + c so you were wrong even if your answer was right
i think it's x+b ?
perhaps i made mistake
someone is going to have to go over this with him I'm too rusty and have a journal to read on some journal article on some histone demethylation protein that is in rice that I'm suppose to care about
Okay... let's recap: \[\Large \int(x^2+b)dx\]
You know that antidifferentiation (integration) is linear, so we can distribute it: \[\Large = \int x^2dx + \int b dx\] Right?
Now all you need to recall is the power rule for integration... \[\Large \int ax^ndx = \frac{ax^{n+1}}{n+1}\color{orange}{+C} \qquad n \ne -1\]
no, i think i should learn more
Not forgetting of course, that \[\Large b = bx^0\]
sorry wait for about...some days i think i have to learn more,and ask some questions :)
i'll keep this question open
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