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Solve for A: B=5/7(A-11)
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\(B=\dfrac{5}{7(A-11)}\) Is this correct?
\[B=\frac{ 5 }{ 7 }(A-11)\]
Even easier :P
First I would divide each side by \(\dfrac{5}{7}\) \(\dfrac{7B}{5}=A-11\) Then you add 11 to both sides, \(\dfrac{7B}{5}+11=A\) Make sense? :)
why is the 7 become the numerator?
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\[A=\frac{ 5 }{ 7 }B+11\] so is this the answer?
Because when you divide by a fraction, you are multiplying by the reciprocal. Lets say you want to do this, \(\dfrac{1}{2}\div\dfrac{3}{4}\) To be able to do this operation you need to multiply the half by the reciprocal of three-fourths. \(\dfrac{1}{2}\times\dfrac{4}{3}\) Which then leads us to the answer, \(\dfrac{4}{6}=\dfrac{2}{3}\) Understand?
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