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Algebra 7 Online
OpenStudy (anonymous):

could someone help me understand this / Inequalities on a number line

OpenStudy (anonymous):

please help!

OpenStudy (ciel21):

The < same means less then only. The < sign with a line under it means less then OR equal to. And the > sign means greater then only, while the > sign with a line under it means greater then OR equal to. Hope I helped!

OpenStudy (anonymous):

thanks..

OpenStudy (ciel21):

is that what you needed help with?

OpenStudy (anonymous):

well not really .. just reading it on a number line.

OpenStudy (anonymous):

nevermind! I got it!!!! thanks soooo much. I see if its a closed dot its going to be greater than or equal to or less than equal too . and if its a open dot its just regular greater than or less than

OpenStudy (ciel21):

okay so 1.Simplify the inequality you're going to graph. Multiply out anything that's in parentheses, and combine numbers that are unattached to variables. -2x2 + 5x < -6(x + 1) -2x2 + 5x < -6x - 6 2.Move all terms to one side so the other is zero. It will be easiest if the highest power variable is positive. Combine common terms (such as -6x and -5x). 0 < 2x2 -6x - 5x - 6 0 < 2x2 -11x - 6 3.Solve for the variables. Pretend that the inequality sign is an equal sign, and find all values of the variable. If necessary, solve by factoring. 0 = 2x2 -11x - 6 0 = (2x + 1)(x - 6) 2x + 1 = 0, x - 6 = 0 2x = -1, x = 6 x = -1/2, x = 6 4.Draw a number line including the variable solutions (in order). 5.Draw a circle on the points. If the inequality symbol is "less than" (<) or "more than" (>), draw an empty circle over the variable solution(s). If it means "less than or equal to" (≤) or "more than or equal to" (≥), then fill in the circle. In this case the equation was greater than zero, so use open circles. 6.Test your solution. Take a number from each of the resulting intervals and plug it back into the inequality. If you get a true statement once solved, shade this region of the number line. In the interval from (-∞,-1/2) we will take -1 and plug it into the original inequality. 0 < 2x2 -11x - 6 0 < 2(-1)2 -11(-1) - 6 0 < 2(1) + 11 - 6 0 < 7 Zero is less than 7 is correct, so shade (-∞, -1/2) on the number line. Next, on the interval from (-1/2, 6) we will use zero. 0 < 2(0)2 -11(0) - 6 0 < 0 + 0 - 6 0 < -6 Zero is not less than negative six, so do not shade (-1/2,6). Lastly, we will take 10 from the interval (6,∞). 0 < 2(10)2 - 11(10) + 6 0 < 2(100) - 110 + 6 0 < 200 - 110 + 6 0 < 96 Zero is less than 96 is correct, so shade (6,∞) as well. Use arrows on the end of shading to indicate that the interval continues into infinity. The completed number line...hope this is what you meant lol

OpenStudy (ciel21):

oh lol cx well youre welcome can i have a medal? :3

OpenStudy (anonymous):

im new to this how do u give medals?

OpenStudy (ciel21):

all you have to do is press best response and it gives the person a medal but you can only give one person the medal and welcome to open study :3

OpenStudy (anonymous):

aww. so ur a teacher

OpenStudy (ciel21):

no lol im only in 7th grade xD

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