Question

medal for help with simplifying please

Answer 1

\[\frac{ 2 }{ z^2 - 36} - \frac{ 1 }{ z^2 + 6z}\]

Answer 2

Cross multiply them together to make it a one fraction
So,

Answer 3

the answer i got is 2 (z - 6) but not sure if that is correct

Answer 4

\[(2/(x-6)(x+6))- (1/x(x+6)\]

Answer 5

@celloscope yes thank you that is what i got as the first step

Answer 6

[2(z^2 + 6z) - z^2+36]/(z^2-36)(z^2+6)

Answer 7

[2z^2+12z-z^2+36]/(z^2-36)(z^2+6)

Answer 8

[z^2+12z+36]/(z^2-36)(z^2+6)
(z+6)(z+6)/(z^2-36)(z^2+6)

Answer 9

So simplify it and tell me

Answer 10

\(\Large{\frac{ 2 }{ z^2 - 36} - \frac{ 1 }{ z^2 + 6z}}\)

First you would need to find a common denominator,

\(\Large{(\frac{z^2+6z}{z^2+6z})(\frac{ 2 }{ z^2 - 36}) -( \frac{ 1 }{ z^2 + 6z})(\frac{z^2-36}{z^2-36})}\)

\(\Large(\frac{2z^2+12z}{z^4-72z^2+1296})-(\frac{z^2-36}{z^4-72z^2+1296})=\)

\(\Large{=\frac{2z^2-z^2+12z-36}{z^4-72z^2+1296}=~?}\)

Answer 11

i factored the fractions first, then found the common denominator of z (z + 6) (z - 6) and ended up with 2 (z - 6)...is this correcct?

Answer 12

\[actually \frac{ 1 }{2(z-6)}\]