A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. How soon did the second train overtake the first?

If 50x represents the distance the slower train travels, then the faster train travels

55(x - 0.5)
55(x + 0.5)
50 + 30x

Question

A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. How soon did the second train overtake the first?

If 50x represents the distance the slower train travels, then the faster train travels


55(x - 0.5)
55(x + 0.5)
50 + 30x

anonymous · Answer

r t = d
Let t be the time in hours for the second train to overtake the first.
$$50*\frac{1}{2}+50 t= 55t$$Solve the above for t.

anonymous · Answer

Verify that t = 5 hours.

anonymous · Answer

ya the answer is 5 but i need the equation.

anonymous · Answer

$$50*\frac{1}{2}+50 t=55t $$is the equation.

The LHS says that when a stop watch starts at the same time the fast train starts, the slow train is at the 25 mile point and moving at 50 mph.

The RHS says that the faster train is eating up track at the rate of 55 miles of track per hour.

anonymous · Answer

but that is not one of the options