Question

Find the zeros of f. (Enter your answers as a comma-separated list.)

(hold on while I copy the equation ><)

Answer 1

\[x ^{2}\left( 2e ^{3x} \right)+8xe ^{3x}+31e ^{3x}+8xe ^{3x}\]

Answer 2

hello
the first step to this problem is to factor out 2e^3x
can you do this for me and put it here?

Answer 3

Okay

Answer 4

x^2+8x+31

Answer 5

don't you mean 16x?
there seems to be 2 8x's

Answer 6

If that works I /might/ be able to solve it. I didn't think of facotring out 2e^3x

And there are, so combine them and you get 16x, but divide them by 2 and it becomes 8, no? In that case the 31 should be 31/2

Answer 7

YES! I got the answer! Thank you so much. :)