Question

9K^3-9m^2K
------------ is equivalent to 3k+ (?)
3K^2-3mK

Answer 1

(A) m
(B) 3m
(C) 1
(D) 2
(E) 3

Answer 2

\[9k^3-9m^2k=9k(k^2-m^2)=9k(k-m)(k+m)\]

Answer 3

Do I distribute? @Mertsj

Answer 4

Factor the denominator and cancel any common factors.

Answer 5

3k(k^3-m) ...?

Answer 6

\[3k^2-3mk=3k(k-m)\]

Answer 7

how did you get rid of the ^3?

Answer 8

The denominator does not have an exponent 3

Answer 9

oh..

Answer 10

\[\frac{9k^3-9m^2k}{3k^2-mk}=\frac{9k(k-m)(k+m)}{3k(k-m)}=3(k+m)\]

Answer 11

Is it B?

Answer 12

yes

Answer 13

thank you!