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the senate has 17 women senators. If you randomly select 3 different senators to visit, what is the probability that: a) all of the senators would be women? b) two of the senators would be women? c)at least one of the senators would be a woman?
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looked good to me
you can use \[\frac{17}{100}\times \frac{16}{99}\times \frac{15}{98}\] or \[\frac{\binom{17}{3}}{\binom{100}{3}}\] you will get the same answer
first method is quicker second method generalizes better for example 2, female, one male \[\frac{\binom{17}{2}\binom{83}{1}}{\binom{100}{3}}\]
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