x+y=4 x-y=2 graph the linear system and determine how many solutions it has.
Do you have any idea how to graph those linear equations?
no sir.
Well, the easiest method of graphing linear equations is to equate it first into y. Example. In your case, we have x+y = 4 and x-y =2 By converting this into y equation, we will have: y = 4-x and y = x-2 Do you know this part?
@MysteryOwl . can you follow?
i never encountered how to convert into y equation.
Do you know transpositions? Let's take a look at this: x+y = 4 What you need to do is to isolate the variable y, there, you need to subtract x from both left and right side. So, x+y - x = 4-x Therefore, y = 4-x Get it now?
yes..
then what should it do after?
Table of values by assigning value to x to solve the value of y. We already have y = 4-x and y= x-2 So usually, we take values from -2 to +2 Therefore, using the equation y=4-x, the table will be. x -2 -1 0 1 2 y Can you complete it?
yes.. :)
and i'll get the ordered pairs?
Yes.
plus on the second eq. x-y=2 if i substitute -1 as x and 3 will the 3 be a -3 since y in the equation is -?
Yes. That is also true. But for easier calculations, we have converted the equation to y = x-2
can you look through my ordered pairs? eq.1 (-2,6) (-1,5) (0,4) (1,3) eq.2 (-1,3) (-2,4) (0,2) (1,1)
You have problems with the eq.2
:o
how?
We have x-y = 2. right? If we let x=-2 we will have -2-y = 2 Therefore, -2+2-y = 2+2 Hence, -y = 4 so y = -4. Got it?
ohh,... can you give me some ordered pairs for 2?
That is why we converted it into y=x-2 so that you can easily compute it. Say x= -1 y = -1-2 Therefore, y = -3
Can you give the other three?
@MysteryOwl ?
sorry.. got from the bathroom.. let me go through it.
Sure.
he'res the other 3 (-2,-4)(0,-2)(-2,-4)
is this correct now?
Yes. Just plot the points on the cartesian plane and graph them. To solve for it solution, just find their intersection points. You can do that algebraically or graphically.
thank you :D now my only problem is this one.. x+2y=-2 -3x-6y=6
Just do the same thing. :)
convert to y equation? :)
Yea.
thanks again..
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