Question

I always have trouble with these problems .... help http://gyazo.com/62bc6503e5033eeabe1c1e7c7f6c2fa4.png

Answer 1

Just take note that \[\frac{ 9 }{ 13 }x\] is same as \[\frac{ 9x }{ 13 }\]
you have more problems?

Answer 2

That doesn't really help... lol
I meant, I have problems with fractions.

Answer 3

get rid of fractions,
multiply thru by 13*4*5

Answer 4

Okay. I thought that was only your problems. Just find out the LCD (Least Common Denominator) so as you'll get an equation with whole numbers. Just what ganeshie said.

Answer 5

Since it is an equation, you can do anything - as long as u do it to both sides.
so simply multiply the LCD : 13*4*5 both sides.
that just cancels out all denominators...

Answer 6

So... I multiply the denominators?

Answer 7

Yes. But never repeat the same denominator.

Answer 8

Why not?

Answer 9

\(\large \frac{9}{13}x + \frac{1}{4} = \frac{2}{5} - \frac{4}{13}x + \frac{2}{5}\)

Answer 10

lets see it done once,
u will get to knw why not, then :)

Answer 11

we have denominators : 13, 4, 5
they're troubling u so get rid of them, by multiplying them both sides :-

\(\large \color{red}{13 \times 4 \times 5} (\frac{9}{13}x + \frac{1}{4}) = \color{red}{13 \times 4 \times 5}(\frac{2}{5} - \frac{4}{13}x + \frac{2}{5})\)

Answer 12

So, would it be \[(9x+4)=(2-4x+2)\] ?

Answer 13

\(\large \color{red}{4 \times 5} \times 9x + \color{red}{13 \times 5} \times 1 = \color{red}{13 \times 4 } \times 2 - \color{red}{4 \times 5} \times 4x + \color{red}{13 \times 4} \times 2\)

Answer 14

it wud become that.
we just take the 13*4*5 inside paranthesis and multiply it wid every term
heard of distributive property before ?
a(b+c) = ab + ac

Answer 15

Yeah..

Answer 16

you will have to see it by urself, me explaining confuses u more im sure.

on left side,
see that 13 cancelled out in first term,
3 got cancelled out in second term,

on right side,
5 got cancelled out in first term,
....

Answer 17

Yeah... I still don't understand. But thanks for trying to help me.

Answer 18

np :)

Answer 19

\(\large \frac{9}{13}x + \frac{1}{4} = \frac{2}{5} - \frac{4}{13}x + \frac{2}{5}\)

multiply denominators' product 13*4*5 both sides :-

\(\large \color{red}{13 \times 4 \times 5} (\frac{9}{13}x + \frac{1}{4}) = \color{red}{13 \times 4 \times 5}(\frac{2}{5} - \frac{4}{13}x + \frac{2}{5})\)

distribute and cancel :-

\(\large \color{red}{4 \times 5} \times 9x + \color{red}{13 \times 5} = \color{red}{13 \times 4 \times 5} \times 2 - \color{red}{4 \times 5} \times 4x + \color{red}{13 \times 5} \times 2\)