Question

absolute deviations of the separating
angles of the clock

Answer 1

what is obvious about this question can we say the time t is less than 12 hours...and can we say the deviations are
\[|f(t)|=(2\pi/3-\theta)t\]
where theta is the deciation from 2pi/3...can this assumption be made

Answer 2

and wat does min of max mean

Answer 3

I would use,
\[f(\theta)=|2\pi/3-\theta t|\]

Answer 4

problem is our function is already given ito t

Answer 5

Sorry, I mean f(t)

Answer 6

And of course,
\[f(t)=|2\pi/3-\omega t|\]

Answer 7

i am goin to post a possible solution from a forum

Answer 8

With
\[\omega=2\pi/T\]and T the period.

Answer 9

Post it, please :)

Answer 10

okay this seems very good logic thou @John_ES

Answer 11

ı thınk u whre on the rıght track

Answer 12

\[\theta_1(t)=\frac{2\pi}{43200}t\\
\theta_2(t)=\frac{2\pi}{3600}t\\
\theta_3(t)=\frac{2\pi}{60}t\]
All in radians.

Answer 13

If I'm not wrong, then
\[f(t)=\frac{2 \pi }{3}-\frac{11 \pi t}{21600}\\
g(t)=\frac{2 \pi }{3}-\frac{708 \pi t}{21600}\\
h(t)=\frac{2 \pi }{3}-\frac{719 \pi t}{21600}\]
Then maximum deviation is for f(t), and its minimum is t=14400/11 s=4/11 hours..

Answer 14

With the absolute value symbols, of course.