Question

How to synthesize 1 gram of potassium sulfate?
So I know one way of synthesizing potassium sulfate is through an acid-base reaction.
2KOH(aq) + H2SO4(aq) -> 2H2O(l) + K2SO4(s)
I also know that the acids and bases will be 6M.
So would I take the 6M acids and bases and the mols in the equation to get the amount (mL) of the reactants to get 1 gram of K2SO4?

Answer 1

For example,
\[6M KOH = \frac{ 2 mol }{ L }\] and then convert to mL?

Answer 2

work "backwards", start by finding how many moles 1g of K2SO4(s).

then using the stoichiometric coefficients you can see that the ratio of K2SO4 to H2SO4 is 1:1, but K2SO4 to KOH is 1:2.

you need the same amount of moles of H2SO4, but twice as many of KOH.

use the formula you posted to find the volume of each reactant: \(M=\dfrac{n_{solute}}{L_{solution}}\)