Question

Suppose that the function f satisfies f'(x)= 3x^2-sinx(pi)x. Then the slope of the line tangent to the graph f at the point x=2 is
A) 12
B)8-(1/pi)
C) 7
D) 12-pi
E)24

Answer 1

\[f'(x)= 3x ^{2}-\sin pix\]

Answer 2

\[f'(x)= 3x ^{2}-\sin (\pi x)\]This?

Answer 3

yes:)

Answer 4

Can you find the derivative?

Answer 5

would it be 6x-cos(pi)x ?

Answer 6

I am not sure if I have to find the derivative since its already giving me the derivative

Answer 7

Oh, you're right. So just plug in \(x=2\).

Answer 8

i tried that but it didnt gave me one of the answers :/

Answer 9

It's one of the answers

Answer 10

\[
3(2)^2-\sin(\pi(2)=3\times 4-0=12
\]

Answer 11

yup

Answer 12

ooh thank you:)