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OpenStudy (anonymous):
The sides of a square are increasing at a rate of 5 m/s. the area of the square is changing at a rate of (blank) m/s^2 when the sides are 30m long.
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OpenStudy (anonymous):
Okay start with: \[
A=x^2
\]
OpenStudy (anonymous):
Can you implicitly differentiate this equation with respect to \(t\)?
OpenStudy (anonymous):
length = 5(t) + length of original side
area = length^2
dl/dt = 5
da/dl = 2(L)
OpenStudy (anonymous):
da/dt = 10(L)
OpenStudy (anonymous):
Don't come up with any explicit equations of \(t\).
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OpenStudy (anonymous):
dA/dx = 2x
OpenStudy (anonymous):
Correct.
OpenStudy (anonymous):
I would think the sides are changing at a rate of 2(x) where x = 30 = length of side
OpenStudy (anonymous):
= 60
OpenStudy (anonymous):
\[
A'=2xx'=2(30)(5)
\]
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OpenStudy (anonymous):
oh because x is a function of time?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
\[
\frac{dA}{dt}=\frac{dA}{dx}\frac{dx}{dt}
\]
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
oh because x is a function of time?
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OpenStudy (anonymous):
Yeah
OpenStudy (anonymous):
Well you just have to remember that derivatives is all about which variable you differentiate.
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