Question

can someone help me with these problems ?

An airplane is travelling north at 578.0 km/h. Ten minutes later it is travelling west at 327.0 km/h. What is the magnitude of the average acceleration vector in m/s2?

From a starting point you travel 45.0 km NORTH, 39.0 km WEST and 46.0 km SOUTH. Determine the angle (in degrees) that your total displacement vector will make with respect to the westerly direction.

A skydiver, who weighs 716.0 N is falling at a constant velocity. If the force of the air resistance acting directly on the skydiver is 48.0 N, what is the force of the air resistanc

Answer 1

A skydiver, who weighs 716.0 N is falling at a constant velocity. If the force of the air resistance acting directly on the skydiver is 48.0 N, what is the force of the air resistance acting on the parachute (in N)?

Answer 2

For the first question, you need to convert all the givens by m/s and the 10 min to seconds. To calculate for acceleration: Since your direction is north then west, you need to get the resultant velocity. After that, divide it by the time traveled. \[acceleration=\frac{ \Delta V }{ \Delta t }\]

-->it's hard to explain all your questions..

Answer 3

for (1) the change in velocity is sqr( 578^2 + 327^2)
in km/hour
change that into meters/ sec

the change in time is 10 min = 600 sec
then find the acceleration just as Data_LG2 explained

Answer 4

For (2), draw a picture

Answer 5

for (3), if you are falling at a constant velocity, then your acceleration is 0, so the forces must balance. Force on parachute + force on man = force due to gravity

Answer 6

thx